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Asp/VB Script Source Codes
Date Format
Date formats
Date Parts
Date Add and Subtract
Date Difference
Is this year a Leap year
How to calculate Julian Date
Date countdown till a given date
First and Last day of Month
Date Format [ Relative to the date as 2/7/2000 10:37:48 AM ]
<%=FormatDateTime(Now(),1) %>
Outputs as : Monday, February 07, 2000
<%=FormatDateTime(Now(),2)%>
Outputs as : 2/7/2000
<%=Now%>
Outputs as : 2/7/2000 10:24:57 AM
Date Part [ Relative to the date 2/7/2000 10:37:48 AM ]
Day
Today is <%=Day(Date)%>
Outputs as : Today is 7
Week
This is week # <%= DatePart("ww",date)%> of the this year
Outputs as : This is week # 7 of this year
This is weekday <%= WeekDay(Date)%> of this year
Outputs as : This is weekday 2 of this year
Today is <%=WeekDayName(WeekDay(Date))%>
Outputs as : Today is Monday
Month
The month Now is <%=Month(Date)%>
Outputs : The month Now is 2
Another way, of saying the current month is <%=(DatePart("m",date))%>
Outputs : Another way, of saying the current month is 2
The MonthName is <%=MonthName(Month(Date))%>
Outputs : The MonthName is February
Year
The year is <%=Year(Date)%>
Outputs : The year is 2000
Date Add and Subtract
Add
Day
2 Days from 2/9/2000 it will be <%=DateAdd("d",2,CDate("2/9/2000"))%>
Outputs : 2 Days from now it will be 2/11/2000
Month
2 Months from 2/9/2000 it will be <%=DateAdd("m",2,CDate("2/9/2000"))%>
Outputs : 2 Months from 2/9/2000 it will be 4/9/2000
Year
2 Years from 2/9/2000 it will be <%=DateAdd("yyyy",2,CDate("2/9/2000"))%>
Outputs : 2 Years from 2/9/2000 it will be 2/9/2002
Subtract
Day
2 Days back from 2/9/2000 it was <%=DateAdd("d",-2,CDate("2/9/2000"))%>
Outputs : 2 Days back from now it was be 2/7/2000
Month
2 Months back from 2/9/2000 it was be <%=DateAdd("m",-2,CDate("2/9/2000"))%>
Outputs : 2 Months back from 2/9/2000 it was 12/9/1999
Year
2 Years from 2/9/2000 it will be <%=DateAdd("yyyy",-2,CDate("2/9/2000"))%>
Outputs : 2 Years back from 2/9/2000 it was 2/9/1998
Date Difference [ Relative Date : 2/7/2000 ]
Day
Its <%=DateDiff("d","2/7/2000","8/15/1947")*-1 %> days between '8/15/1947' and
'2/7/2000'
Outputs : Its 19169 days between '8/15/1947' and '2/7/2000'
Week
Its <%=DateDiff("ww","2/7/2000","8/15/1947")*-1 %> weeks between '8/15/1947' and
'2/7/2000'
Outputs : Its 2739 weeks between '8/15/1947' and '2/7/2000'
Month
Its <%=DateDiff("m","2/7/2000","8/15/1947")*-1 %> months between '8/15/1947' and
'2/7/2000'
Outputs : Its 630 months between '8/15/1947' and '2/7/2000'
Quarter
Its <%=DateDiff("q","2/7/2000","8/15/1947")*-1 %> quarters between '8/15/1947'
and '2/7/2000'
Outputs : Its 210 Quarters between '8/15/1947' and '2/7/2000'
Year
Its <%=DateDiff("yyyy","2/7/2000","8/15/1947")*-1 %> years between '8/15/1947'
and '2/7/2000'
Outputs : Its 53 between '8/15/1947' and '2/7/2000'
Leap Year
<%
Dim lYear
lYear = Year(CDate("2/9/2000"))
leap_yes = "is a leap year"
leap_no = "is not a leap year"
If (lYear mod 4 = 0) AND ((lYear mod 1 0) OR (lYear mod 4 = 0)) then
' It is a Leap Year
Response.Write lYear & " " & leap_yes
else
' it is not a leap year
Response.Write lYear & " " & leap_no
End if
%gt;
Outputs : 2000 is a leap year
Julian Date
<%
d0=DateSerial ("2000", "1", "1")
d1=Date - d0 + 1
Response.write "Today's Julian Date Is #" & d1
%>
Outputs : Today's Julian Date Is #38
Date Countdown
<%
dim strDateTime
strDateTime = CDate("2/9/2000")
strFutureDay = #12/31#
Response.write "There are" & INT(strFutureDay - strDateTime) & " more days till
December 31st."
%>
Outputs : There are 327 more days till December 31st.
How to find first and last day of the month
Calculate first date of current month
<%
BaseDate = CDate("2/9/2000")
FirstOfMonth = DateSerial(Year(BaseDate), Month(BaseDate) + iOffset, 1)
Response.write "The first date of this month is " & FirstOfMonth
%>
Outputs : The first date of this month is 2/1/2000
Calculate last date of current month
<%
BaseDate = CDate("2/9/2000")
EndOfMonth = DateSerial(Year(BaseDate), Month(BaseDate) + 1, 0)
Response.write "The last date of this month is " & EndOfMonth
%>
Outputs : The last date of this month is 2/29/2000
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